Vermutung meinerseits: 22-Ohm-Widerstände sind entweder eine mir noch unbekannte Landplage, oder sie vermehren sich wie die Karnickel, wenn man sie dunkel und staubig bei Onkel Max lagert.
Obiges Sortiment Hochlastwiderstände x3 hat ergeben:
vertikal (tüte1 + tüte2 + tüte3) = total
22 ohm, 9w (21 + 20 + 21) = 62
39 ohm, 17w (5 + 5 + 5) = 15
2,2k, 11w, 5% (1 + 2 + 2) = 5
8,2k, 9w, 5% (2 + 1 + 0) = 3
4,7k, 9w, 5% (0 + 2 + 1) = 3
39k, ?, 5% (76 21 FV75) =(1 + 0 + 1) = 2
4,7k, 9w (1 + 0 + 0) = 1
20ohm, 7w, 5% (0 + 0 + 1) = 1
axial
22 ohm, 4w (15 + 14 + 15) = 44
4,7mega, ?, 5% (10 + 10 + 10) = 30
470 ohm, 5w (5 + 5 + 5) = 15
47ohm (?! gelb, violett, gold, gold, gelb) =(5 + 5 + 5) = 15
4,7ohm, ? (4 + 6 + 4) = 14
470ohm, ? (4 + 4 + 4) = 12
100mega (!) , ? (MD HGR 0939 100M +-10%) =(2 + 5 + 3) = 10
0,92 ohm, ? (5 + 5 + 0) = 10
470 ohm, ?, 5% (kka5 470ohm5%2G und KKA 470ohm5%1F) =(4 + 2 + 2) = 8
220ohm, ? (3 + 2 + 3) = 8
390ohm, ? (2 + 2 + 3) = 7
2,4 ohm, ?, 5% (kka7 2,4ohm5%11F) =(2 + 2 + 2) = 6
270ohm, ?, 5% (3 + 0 + 2) = 5
10mega, 5% (0 + 0 + 5) = 5
1,5ohm, ?, ? (1R5KV) =(1 + 2 + 1) = 4
150ohm, ? (1 + 3 + 0) = 4
1,0ohm, ? (1 + 2 + 1) = 4
240ohm, ? (1 + 0 + 3) = 4
47ohm, ? (3 + 0 + 0) = 3
1,5ohm, 4w (0 + 1 + 1) = 2
8,0k, 1w, 1% (2 + 0 + 0) = 2
1,8k, ?, ? (1K8IT) =(1 + 0 + 1) = 2
1,5ohm, ? (0 + 1 + 1) = 2
12k, ?, ? (VITROHM H12000ohm) =(1 + 0 + 0) = 1
100ohm, 4w (0 + 1 + 0) = 1
360ohm, 1w, 1% (0 + 1 + 0) = 1
7ohm, 1w, 1% (0 + 1 + 0) = 1
1,5kohm, ? (0 + 0 + 1) = 1
summe (106 + 104 + 103) = 313
defekt (lose kappen)
8,0k, 1w, 1%, defekt (0 + 0 + 1) = 1
2,5mega, 1w, 1%, defekt (0 + 1 + 0) = 1
bonus:
10µF, 40V (1 + 0 + 1)